Final answer:
The magnitude of the pole-vaulter's acceleration as he comes to rest on the pad is 0 m/s^2.
Step-by-step explanation:
To find the magnitude of the pole-vaulter's acceleration as he comes to rest on the pad, we can use the equation that relates acceleration, initial velocity, final velocity, and displacement:
vf^2 = vi^2 + 2ad
Since the pole-vaulter is nearly motionless at the highest point, his final velocity (vf) is 0. Therefore, we can rewrite the equation as:
0 = vi^2 + 2ad
Using the given values, the initial velocity (vi) is 0 m/s, the displacement (d) is 80 cm = 0.80 m, and the acceleration (a) is what we are solving for.
0 = 0^2 + 2a(0.80)
Simplifying the equation gives:
0 = 0 + 1.6a
Dividing by 1.6 gives:
a = 0 m/s^2
Therefore, the magnitude of the pole-vaulter's acceleration as he comes to rest on the pad is 0 m/s^2.