Question

15.

At 9:00 on Saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path.The bicyclist heading north is riding 4 km/hour faster than the bicyclist heading south. At 10:15, they are 40 km apart. Find the two bicyclists’ rates.

northbound bicyclist = 19 km/h; southbound bicyclist = 15 km/h

northbound bicyclist = 18 km/h; southbound bicyclist = 14 km/h

northbound bicyclist = 18 km/h; southbound bicyclist = 13 km/h

northbound bicyclist = 16 km/h; southbound bicyclist = 10 km/h

Answer 1

Answer:northbound bicyclist = 18 km/h; southbound bicyclist = 11 km/h

Answer 2

In 1.25 hours, their combined speed is 40 km, so their speed per hour is 32 km/h

So the answer is B. northbound bicyclist = 18 km/h

southbound bicyclist = 14 km/h

Explanation:

the speed of the slower is x and the faster x+4 km/h

that equals 32 km and the speed of the slower is 14 km/hr and the faster 18 km/hr.

in 1h15m the slower goes 17.5 km and the faster 22.5 km