Question

: Two cars are traveling on a desert road, as shown below. After 5.0 s, they are side by side at the next telephone pole. The distance between the poles is 70.0 m. Identify the following quantities:

a. the displacement of car A after 5.0 s
b. the displacement of car B after 5.0 s
c. the average velocity of car A during 5.0 s
d. the average velocity of car B during 5.0 s

Answer 1

The displacement of car A and car B after 5.0 s is 70.0 m. The average velocity of car A and car B during 5.0 s is 14.0 m/s.

Step-by-step explanation:

a. The displacement of car A after 5.0 s is 70.0 m because it is side by side with the next telephone pole.

b. The displacement of car B after 5.0 s is also 70.0 m because it is side by side with the next telephone pole.

c. The average velocity of car A during 5.0 s can be calculated by dividing the displacement by the time = 70.0 m / 5.0 s = 14.0 m/s.

d. The average velocity of car B during 5.0 s is also 14.0 m/s because it covered the same displacement in the same time.

Answer 2

"Displacement" = (straight-line distance and direction from start-point to end-point)

a). From the first picture to the the second picture, Car-A has moved forward by one telephone pole. That's 70 m. His displacement during that five seconds is 70-m in the direction of whatever direction the road is heading.

b). From the first picture to the the second picture, Car-B has moved forward by TWO telephone poles. That's 140 m. His displacement during that five seconds is 140-m in the direction of whatever direction the road is heading.

Average velocity = (displacement) / (time for the displacement)

c). Car-A average velocity = (70 m)/(5 sec) = 14 m/s in the direction of the road.

d). Car-B average velocity = (140m)/(5sec) = 28 m/s in the direction of the road.