Question

What is the distance around a triangle that has sides measuring 2 1/8 feet, 3 1/2 feet, and 2 1/2 feet?

A- 7 1/8 feet

B- 7 9/24 feet

C- 8 feet

D- 8 1/8


(Show work pleae! ^v^)

Answer 1

Hi!
A is the answer:⏬⏬⏬⏬⏬⏬⏬⏬

The distance around a triangle, better noun as de "perimeter of a triangle"

is the total distance around the outside, which can be found by adding together the length of each side.

Perimeter (P) = Length A + Length B + Lenght C

In this case, we know that each side measure 2 \frac{1}{8}81​ feet, 3 \frac{1}{2}21​ feet, and 2 \frac{1}{2}21​feet but we have to rewrite each one of this mixed fractions as improper fractions:

2 \frac{1}{8}81​ = \frac{16 + 1}{8}816+1​ = \frac{17}{8}817​

3 \frac{1}{2}21​ = \frac{6 + 1}{2}26+1​ = \frac{7}{2}27​

2 \frac{1}{2}21​ = \frac{4 + 1}{2}24+1​ = \frac{5}{2}25​

Then we just add all of them to find the perimeter:

 = \frac{17 + 28 + 20}{8}817+28+20​ = \frac{65}{8}865​

A: The distance around a triangle is \frac{65}{8}865​feet

Answer 2

Answer: Choice D) 8 & 1/8

This is read as "Eight and one-eighth"

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You want the perimeter so you'll add the three fractions to add up the three side lengths.

1/2 is the same as 4/8 (since 4 is half of 8). You can think of having a cake that is cut up into 8 equal slices. If you take 4 of those slices, then you take half of the cake.

So the value 3&1/2 is the same as 3&4/8. Similarly, 2&1/2 is equivalent to 2&4/8

We want to add the three mixed numbers: 2&1/8, 3&4/8, 2&4/8

Add up the fractional parts: 1/8+4/8+4/8 = (1+4+4)/8 = 9/8 = 1&1/8

The whole part '1' carries over to the other whole parts.

Add up the whole parts: 2+3+2 = 7

Then add in the carry: 7+1 = 8

Overall, the three numbers {2&1/8, 3&4/8, 2&4/8} add up to 8&1/8 which is the final answer (choice D)