Question

Larger of two numbers is nine less than four times the smaller number if the sum of two numbers is 76 find both numbers

Answer 1

x + y = 76

x = 4y - 9

4y - 9 + y = 76

5y = 65

y = 13

13 + x = 76

x = 63

Answer 2

17 and 59

Explanation:

Given: Larger of two numbers is nine less than four times the smaller number. The sum of two numbers is 76.

To find: Both the numbers

Solution:

Let the smaller number be x and the larger number be y.

It is given that the sum of the numbers is 76.

So,
`x+y=76`

Also, the larger number is 9 less than 4 times the smaller number. So, we have
`y=4x-9`

On substituting
`y=4x-9` in
`x+y=76` we get

`x+4x-9=76`

`5x-9=76`

`5x=76+9`

`5x=85`

`x=(85)/(5)`

`x=17`

So, the smaller number is 17

larger number is
`4(17)-9=59`

Hence, the smaller number is 17 and the larger number is 59.