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Amount (mol) of Mn atoms in 62.0 mg of Mn

1 Answer

7 votes

Answer:

0.0011 mol

Solution:

Data Given:

Mass of Mn = 62.0 mg = 0.062 g

Atomic Mass of Mn = 54.94 g.mol⁻¹

Calculate Moles of Mn as,

Moles = Mass ÷ M.Mass

Putting values,

Moles = 0.062 g ÷ 54.94 g.mol⁻¹

Moles = 0.0011 mol

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