Answer:
The determinants can be used to solve for x and y in the system of linear equations below are:

Explanation:
We are given a system of linear equations as:

and

Hence, we can form a matrix with the help of these equations as:

where A is a matrix formed by the coefficients of x and y and is a 2×2 matrix.
and b is a matrix formed by the term after equality and is a 2×1 matrix.
Hence, we have:

As we know that:

where,
