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A drug that it will decrease the bacteria cells by 5% every hour. If you start with 1500 bacteria cells, how many will be present after 8 hours?

(I need this written as a y= equation)

User Yingying
by
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1 Answer

5 votes

after 8 hours there are 995 bacteria cells left

let y be the amount after 8 hours

the multiplying factor is 100 - 5 = 95 % = 0.95

y = 1500 ×
(0.95)^(8) = 995




User Manoj Selvin
by
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