Answer: Cost of tickets for adults = $22
Cost of tickets for children = $15
Total number of tickets sold = 732
Total receipts = $12,912
Let x be number of adult ticket's sold and y be the number of child ticket's sold.
Therefore, we have:
--------------- equation 1
![x=732-y](https://img.qammunity.org/2019/formulas/mathematics/college/vz6rllhmzzku2r1yykl7n30nn3vci09tnp.png)
Also, we have:
![22 x+15y=12,912](https://img.qammunity.org/2019/formulas/mathematics/college/utx5a7ag4zb0cqm15kfhdnkdqk57vcx667.png)
Now, let's substitute the value of x:
![22 (732-y)+15y=12912](https://img.qammunity.org/2019/formulas/mathematics/college/za64s2bb7c4qgr96x6qs9yccr0wybw405e.png)
![16104-22y+15y=12912](https://img.qammunity.org/2019/formulas/mathematics/college/ytpxcklnpucyzbpb5vxen7ateog6cyf9xz.png)
![16104-7y=12912](https://img.qammunity.org/2019/formulas/mathematics/college/yhejvqbs9g244sk2ocjo186e7w2u11gn60.png)
![7y=16104-12912](https://img.qammunity.org/2019/formulas/mathematics/college/n4q4w6asj3dodp3rzgllqvfss3td07c1c7.png)
![7y=3192](https://img.qammunity.org/2019/formulas/mathematics/college/b850s94cpo6pcrz047hlb7r0of0afqou4h.png)
![y=(3192)/(7) =456](https://img.qammunity.org/2019/formulas/mathematics/college/gc6qyp4ur3eniyy6iy35ordrqxvkx72b6g.png)
Now, let's substitute the value of y=456 in equation 1, we have:
![x+456=732](https://img.qammunity.org/2019/formulas/mathematics/college/wyqfir00rykd2kn73dpcif6iqxbcd17gs0.png)
![x=732-456](https://img.qammunity.org/2019/formulas/mathematics/college/ofsf32lf7ikhkatfjimuaose7msub1mqi6.png)
![x=276](https://img.qammunity.org/2019/formulas/mathematics/college/l0shqzdf7xm4zff94z6fdprdd25od6fol8.png)
Therefore, the number of child ticket's sold is 456 and number of adult ticket's sold is 276