Question

A certain shade of blue has a frequency of 7.05 × 1014 hz. What is the energy of exactly one photon of this light?

Answer 1

Energy of photon is equal to the product of Planck's constant and frequency.

The mathematical expression is given as :

`E = h\\u`

where,

E = energy of photon

h = Planck's constant i.e.
`6.626 * 10^(-34) Js`

`\\u` = frequency

Put the given values of frequency and Planck's constant in above formula, we get

`E =6.626 * 10^(-34) Js* 7.05 * 10^(14) Hz`

=
`46.7133* 10^(-20) Js Hz`

Since, Hz is equal to
`second^(-1)`

Thus, energy of photon =
`46.7133 * 10^(-20) J` or
`4.67133 * 10^(-19) J`