Question

How much work does the electric field do in moving a proton from a point with a potential of +175 v to a point where it is -55 v ? Express your answer in joules?

Answer 1

as per the question the proton is taken from the point of 175 volt to the point of -55 volt.

the work done in case of electric filed is given as

`W=Vab *q`

where Vab is the potential difference between two points.

Vab =Va-Vb

=175-[-55]volt

= 230 volt

the charge of proton is
`q=1.602*10^(-19)`

hence the work done will be-

W=230 volt ×
`1.602*10^(-19) coulomb`

=368.46
`*10^(-19)` joule [ans]