Question

During 9.97 seconds a motorcyclist changes his velocity from v1,x = -36.5 m/s and v1,y = 10.9 m/s to v2,x =-21.9 m/s and v2,y = 27.5 m/s. Find the components of the motorcycle\'s average acceleration during this process, aav,x and aav,y.

Answer 1

Average acceleration is defined as

`a = (v_f - v_i)/(t)`

here

`v_f = final\: speed`

`v_i = initial\: speed`

`t = time`

now for x direction we can say

`a_x = (v_(2x) - v_(1x))/(t)`

`a_x = (-21.9 + 36.5)/(9.97)`

`a_x = 1.46 m/s^2`

Similarly for Y direction

`a_y = (v_(2y) - v_(1y))/(t)`

`a_y = (27.5 - 10.9)/(9.97)`

`a_y = 1.66 m/s^2`

so above is the acceleration in x and y directions