Question

Find the indicated trigonometric value in the specified quadrant. Function quadrant trigonometric value csc θ = –5 iii cot θ

Answer 1

cot θ = square root 24

Step-by-step explanation:

Because of the Pythagorean Identities.

1+ cot^2 x = csc^2 x .

So 1+ cot^2 θ = (-5)^2,

1+cot^2 θ = 25,

cot^2 θ = 25 - 1= 24,

cot θ = square root of 24 ( the answer is positive, because in Quad 3, tangent and its reciprocal are positive.( tan t = 1/cot t)

So the ANSWER is the square root of 24.

Answer 2

csc = 1/sin, so sin= -1/5

sin²+cos²=1 so sin=√(24/25)=2√6/5

cot=cos/sin or 2√6/5 * -5/1 = -2√6