Question

What is the theoretical yield of carbon dioxide gas on complete combustion of 250 grams of naproxen?

Answer 1

Complete combustion of naproxen takes place in excess of oxygen thus, naproxen is a limiting reactant and amount of carbon dioxide produced from it is theoretical yield of carbon dioxide.

The balanced chemical reaction for combustion of naproxen is as follows:

`C_(14)H_(14)O_(3)+16O_(2)\rightarrow 14CO_(2)+7H_(2)O`

From the balanced chemical reaction, 1 mole of naproxen
`C_(14)H_(14)O_(3)` gives 14 mol of
`CO_(2)`.

The mass of naproxen is given 250 g, molar mass is 230.259 g/mol thus, number of moles will be:

`n=(m)/(M)=(250 g)/(230.259 g/mol)=1.0857 mol`

Thus, number of moles of
`CO_(2)` obtained from 1.0857 mol of naproxen will be:

`n_{CO_(2)}=14* 1.0857 mol=15.2 mol`

Now, convert this into mass as follows:

`m=n* M`

Molar mass of
`CO_(2)` is 44 .01 g/mol thus,

`m=15.2 mol* 44.01 g/mol\approx 669 g`

Thus, theoretical yield of
`CO_(2)` is 669 g.