Question

A line passes through the point (-1,4) and the point (3,4) what is the equation of the line.

Answer 1

M=y2-y1/x2-x1 (-1,4)(3,4) M=4-4/3-(-1) M= 0/4 M=0 Now get one of the points (3,4) Y=mx+b 4=0(3)+b 4=b Equation Y=4

Answer 2

The generic equation of the line is:

`y-yo = m (x-xo)`

Where,

m: slope of the line

(xo, yo): ordered pair that belongs to the line

The slope of the line is given by:

`m = (4-4)/(3 - (- 1))`

`m = (4-4)/(3 + 1)`

`m = (0)/(4)`

`m = 0`

By choosing an ordered pair we have:

`(xo, yo) = (3,4)`

Then, replacing values we have:

`y-4 = 0 (x-3)`

Rewriting we have:

`y = 4`

Answer:

The equation of the line is:

`y = 4`