Can somebody please help me? 1.) If √x = 3, then what is the minimum value of x? 2.) (6)/(2\pi )y² ÷ 0.4y/x Leave your answer in terms of pi.

Question

Can somebody please help me?

1.) If √x = 3, then what is the minimum value of x?

2.)
`(6)/(2\pi )`y² ÷ 0.4y/x
Leave your answer in terms of pi.

Answer 1

Part A

We know that √x = 3

Squaring both sides

x = 3²

⇒ x = 9

Hence, the value of x or the minimum value of x is 9

Part B

(
`(6)/(2\pi )`*y²) ÷ (0.4*
`(y)/(x)`) = (
`(6)/(2\pi )`*y²) *
`(x)/(0.4y)`

⇒ (
`(6)/(2\pi )`*y²) ÷ (0.4*
`(y)/(x)`) =
`(7.5)/(\pi y)`*yx