Question

Write the chemical symbols for three different atomic cations that all have 14 protons

Answer 1

The cations are
`Si^+,Si^(2+),Si^(3+)`

Step-by-step explanation:

Atomic number = Number of protons present in the nucleus of an atom of the element

Number of protons =14

Atomic number of an element will be 14.

The name of the element with 14 atomic number is silicon. It has equal number of electrons. Since an atom is a neutral species.

After loosing electrons atom gain positive charge.

`[Si]=1s^22s^22p^63s^23p^2`

After losing an electron is becomes
`Si^(+)`

`[Si^+]=1s^22s^22p^63s^23p^1`

After losing 2 electron is becomes
`Si^(2+)`

`[Si^(2+)]=1s^22s^22p^63s^23p^0`

After losing 3 electron is becomes
`Si^(3+)`

`[Si^(3+)]=1s^22s^22p^6`

Answer 2

The symbols for three different cations with 14 protons are Si²⁺, Si⁴⁺, and Si³⁺.

An element with 14 protons must be silicon, Si.

Its electron configuration is [Ne] 3s²3p², so it could lose up to four valence electrons.

The most likely cations are Si²⁺, Si⁴⁺, and Si³⁺ (or Si⁺).