Question

Evaluate 2b^2-4a+4a^2 for a= 3 and b= -8

Answer 1

Given a = 3 and b = - 8 ,


= > 2b² - 4a + 4a²

= > 2( - 8 )² - 4( 3 ) + 4( 3 )²

= > 2( 64 ) - 4( 3 ) + 4( 9 )

= > 128 - 12 + 36

= > 116 + 36

= > 152




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Answer 2

Hey there!!

The given equation : 2b² - 4a + 4a²

Where, a = 3 and b = -8

Now, we will have to substitute these values in the equation given above

2 ( - 8 )² - 4 ( 3 ) + 4 ( 3 ) ²

( -8 )² = 64

Because -8 × -8 = 64 . As ( - ) × ( - ) = ( + )

negative × negative = positive

Now, moving on

2 ( 64 ) - 4 ( 3 ) + 4 ( 9 )

128 - 12 + 36

116 + 36

The required answer is 152.

Hope my answer helps!!