a) The reduction reaction for Cu2O is
Cu2O + H2 ---> 2Cu(s) + H2O
b) the enthalpy of reaction is
ΔHrxn = ∑ΔHformation of products - ∑ΔHformation of reactants
We know that
ΔHformation of elements in their native state = 0 = ΔHf (H2) = ΔHf (Cu)
ΔHrxn = ΔHf (H2O) - ΔHf (Cu2O) = -247.73 - (-175.31) = -72.42 kJ
So as enthalpy of reaction is negative the reaction is exothermic and heat will be evolved during the reaction