Question

The length of a rectangle is 88 inches longer than the width. If the perimeter of the rectangle is 7272 ​inches, find the measures of the length and width.

Answer 1

The perimeter (IP) of a rectangle is

P = 2(length + width)

let width = w then length = w + 88

P = 2(w+w+88) = 2(2w+88) = 4w+176

Thus P = 4w+176 = 7272

hence 4w = 7272 - 176 = 7096

so w = 7096/4 = 1774

width = 1774 inches and length = w+88 = 1774+88 = 1862 inches