Question

Solve the following system of equations.

x + 2y − 6 = z
3y − 2z = 7
4 + 3x = 2y − 5z

Answer 1

3y-2z=7

y=
`(2z+7)/(3)`......equation(1)

Given x+2y-6=z

x=z-2y+6

putting value of y from equation(1)

By simplifying x=
`(-z+4)/(3)`.....Equation(2)

Now putting the value of x and y in term of z in 3rd given equation

i.e 4+3x=2y-5z

i.e 2y-5z-3x=4

i.e 2(
`(2z+7)/(3)`)-5z-3(
`(-z+4)/(3)`)=4

By simplifying we will get -8z+14=24

i.e z=
`(-5)/(4)`

Now putting z value in Equation(1);y=3/4

And putting z value in Equation(2);x=7/3 (Answer)