Question

The u.S. Mint produced pure silver quarter commemorative coins in 1992, each coin weighing 5.67 g. How many silver atoms are present in each coin?

Answer 1

Mass of each silver coin = 5.67 g

Molar mass of silver = 107.87 g/mol

Calculating the moles of silver from given mass and molar mass of silver:

`5.67 g Ag*(1molAg)/(107.87g) =0.0526molAg`

Calculating the atoms of silver in 0.05260 mol using the conversion factor,
`1mol=6.022*10^(23)atoms`:

`0.05260 mol*(6.022*10^(23)atoms )/(1mol) =3.17*10^(22)atoms`

Therefore,
`3.17*10^(22)`atoms of silver are present in each coin.