Question

Assume that the diffusion coefficient of glucose is 5.70 × 10−7 cm2/s. Calculate the time it would take for a glucose molecule to diffuse 11.3 μm.

Answer 1

To calculate the time it takes for a glucose molecule to diffuse 11.3 μm, use the equation t = Xrms^2 / (2D), where Xrms is the distance and D is the diffusion coefficient. Plug in the values and calculate the time.

Step-by-step explanation:

To calculate the time it takes for a glucose molecule to diffuse a distance of 11.3 μm, we can use the relationship between diffusion coefficient, distance, and time. The average distance a molecule travels by diffusion in a given time is given by the equation Xrms = √(2Dt), where Xrms is the distance, D is the diffusion coefficient, and t is the time. Rearranging the equation, we have t = Xrms^2 / (2D). Plugging in the given values, we have t = (11.3 μm)^2 / (2 * 5.70 × 10^-7 cm^2/s). Evaluating this expression gives us the time it would take for a glucose molecule to diffuse 11.3 μm.

Answer 2

The diffusion coefficient of glucose is
`5.70* 10^(-7)cm^(2)/s`. Glucose molecule diffuse to
`11.3\mu m`, time for diffusion can be calculated as follows:

`t=(x^(2))/(2D)`

To calculate the time first convert x into cm

`1\mu m=10^(-6) m`

Also,

`1 m=100 cm`

Thus,

`10^(-6) m=10^(-4)cm`

and,

`11.3\mu m=11.3* 10^(-4) cm`

Putting the values,

`t=((11.3* 10^(-4) cm)^(2))/(2(5.70* 10^(-7)cm^(2)/s))=1.12 s`

Therefore, time taken for diffusion will be 1.12 s.