Total volume required = 100mL
The concentration of carbonic acid = 0.025
Let concentration of sodium bi carbonate = [NaHCO3]
From Hendersen Hassalbalch's equation for buffers
pH = pKa + log [salt] / [acid]
pKa of carbonic acid = 6.35
7.25 = 6.35 + log [NaHCO3] / 0.025
0.9 = log [NaHCO3] / 0.025
Taking antilog
7.943 = [NaHCO3] / 0.025
[NaHCO3] = 7.943 X 0.025
[NaHCO3] = 0.199 M
Volume is 100mL
Moles of NaHCO3 = molarity X volume (L) = 0.199 X 0.1 = 0.0199
Mass of NaHCO3 = moles X molar mass = 0.0199 X 84 = 1.672 g
moles of H2CO3 = molarity X volume (L) = 0.025 X 0.1 = 0.0025
Mass of H2CO3 = moles X molar mass = 0.0025 X 62 = 0.155 g