Question

A church luncheon made $842. Adult tickets cost $10 each and children's tickets cost $6 each. The number of children was 12 more than twice the number of adults. How many of each ticket were sold?

Answer 1

Solution: Let
`x` be the number of adult ticket's.

The number of child ticket
`=2x+12`

We are given, that an adult ticket cost's $10 and child ticket costs $6. Also the church luncheon made $842.

Therefore,

`x * 10 + (2x+12)6=842`

`10x+12x+72=842`

`22x=842-72`

`22x=770`

`x=(770)/(22)=35`

Therefore, the number of adult ticket's sold = 35

And the number of child ticket's sold = 2 x 35 + 12 = 70 + 12 = 82