Answer:
option A
Explanation:
A card is Chosen at random from a deck of 52 cards
there are 4 aces in the deck of 52 cards
Probability of picking a ace = total ace cards divide by total number of cards
![P(first ace)=(4)/(52) =(1)/(13)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/x4a4o6wgg65t3jd45m5e110k7ei9sep8ih.png)
it is replaced and a second card is chosen
So total cards = 52 and ace =4
![P(second ace)=(4)/(52) =(1)/(13)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/bqrc21uitjyqdcgb1bfvk7d8dizb2a970r.png)
P(both are ace)=
![P(first ace) \cdot P(second ace)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/hup1ptwiwyw6f2wqo9nfgnceuqjyfqhoku.png)
=
![(1)/(13) \cdot (1)/(13) =(1)/(169)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/297xw4d9tdw0bfujtoy7wc1pwh5ya1zf30.png)
option A