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HELP ASAP!!!!! PLEASE!!! :(

HELP ASAP!!!!! PLEASE!!! :(-example-1
User PaulP
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Look at the picture.


\alpha=(360^o)/(8)=45^o

We know: The sum of measures of interior angles in the triangle is equal 180°.

Therefore:


\alpha+2\beta=180^o\\\\45^o+2\beta=180^o\ \ \ |-45^o\\\\2\beta=135^o

When we add up the Interior Angle and Exterior Angle we get a straight line 180°. They are "Supplementary Angles".


\gamma=180^o-2\beta\to\gamma=180^o-135^o=45^o

Answer: The measure of an exterior angle of a regular oktagon is equal 45°.

HELP ASAP!!!!! PLEASE!!! :(-example-1
User Watcom
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