Question

A kettle of water is at 14.5°C. Its temperature is then raised to 50.0°C by supplying it with 5,680 joules of heat. The specific heat capacity of water is 4.186 joules/gram degree Celsius. What is the mass of water in the kettle? Express your answer to three significant figures. The mass of the water in the kettle is grams.

Answer 1

38.2

Step-by-step explanation:

Answer 2

Answer:- 38.2 g.

Solution:- The equation used for solving this type of calorimetry problems is:

`q=mc\Delta T`

where, q is the heat energy, m is mass, c is specific heat and delta T is the change in temperature.

Water temperature is increasing from 14.5 degree C to 50.0 degree C.

`\Delta T=50.0-14.5` = 35.5 degree C

q is given as 5680 J and specific heat value is
`4.186(J)/(g.^0C)` .

The equation could be rearranged for m as:

`m=(q)/(c*\Delta T)`

Let's plug in the values in it:

`m=(5680)/(4.186*35.5)`

m = 38.2 g

So, the mass of water in the kettle is 38.2 g.