1.
So remember that with more than one pair of parentheses, you have to start from the inside and make your way outside.
Firstly, on the left side, solve 5+2 and on the right side solve 4 × 3:
![4[3(7)]=95-12](https://img.qammunity.org/2019/formulas/mathematics/middle-school/pik7a9n86zg420nr8b6d47hptp7su1ifyi.png)
Next, on the left side, solve 3 × 7 and on the right side solve the subtraction:
![4[21]=83](https://img.qammunity.org/2019/formulas/mathematics/middle-school/vy6ks36gs0u60lh9uypoi7snbxgdgf0ir4.png)
Lastly, solve the remaining multiplication on the left side and the answer is
![84= 83](https://img.qammunity.org/2019/formulas/mathematics/middle-school/c7sq9vkashbrgwdokn21hcex8x38kmhkmz.png)
Since 84 is not equal to 83, the correct answer is the second option.
2.
For this, plug 5 into the z variable to solve.
![3*5=2*5+5\\15=10+5\\15=15](https://img.qammunity.org/2019/formulas/mathematics/middle-school/a3qawe652w8072zt0g5fhao1uln23u9wi0.png)
Since 15 = 15 is true, your answer is the first option.
3.
So for this, it's a similar process as Question 2 except that you are plugging in 0 into the x variable to solve:
![8-4*0=4*0\\8-0=0\\8=0](https://img.qammunity.org/2019/formulas/mathematics/middle-school/be8yacmfncd2qps2a7umjb83450z5n2pyj.png)
Since 8 = 0 is a false statement, the correct answer is the second option.