Answer:
D) FeO and CCl4 - One has charges that keep the ions bonded and the other does not.
Step-by-step explanation:
Hello,
In this case, for the iron (II) oxide, in order to know its formula, it is necessary to realize that the (II) indicates the oxidation state it has, it meas +2 from the roman number translation, in such a way, by knowing oxygen works with -2, therefore, the formula turns out:
![Fe^(+2)O^(-2)\rightarrow Fe_2O_2 \rightarrow FeO](https://img.qammunity.org/2019/formulas/chemistry/high-school/gkw7rathw0v0wwmo5q73t8n17hdkcuuksm.png)
In addition, for carbon tetrachloride, the prefix tetra before chloride, points out there are four chlorined bonded to the carbon, that is why its formula is:
![CCl_4](https://img.qammunity.org/2019/formulas/chemistry/high-school/iapbjwbjcmc19ctsxwg2g1qokqjd6bg7x4.png)
In such a way the answer is D) FeO and CCl4 - One has charges that keep the ions bonded and the other does not.
Best regards.