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Using the formula for calculating Kinetic Energy (KE), what is the KE of a truck that weighs 1,200 kg and has a velocity of 6 m/s?

User Kathrice
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E = \frac 1 2 m v^2= \frac 1 2 ( 1200)6^2 = 21600 \textrm{ joules}


User Chrisdowney
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