resolved for the constant speed as the ratio of distance and time. We have B as the speed, the, as the distance at the at the time it is given that the bus leaves easter and other exactly six o'clock in the morning In Travis at a constant speed of 54.3 mph to Austin, which is located at a distance of 190 miles away. We want to find the arrival time. So first is that satisfying the time of travel to suffer the time from the given equation. And we have B equals distance divided by the speed. The distance is 190 miles and the speed is 54.3 mph. We get time here in terms of R. S. S 3.5, So it takes three hours and three hours and 30 minutes to travel, he said distance. So if it's if the bus departs at the at the time of six of clubs, So three hours and 30 minutes after that, it will arrive to Austin. So that means the arrival time will be nine 30 in the morning, So that's three hours and 20 minutes. Oh, after six o'clock. So I hope everything is clear.