Question

What is the maximum mass of ethyl alcohol you could boil with 1000 j of heat, starting from 22 ∘c?

Answer 1

1000 = m*2400*(78-22) + m*8.79*10^5

1000= 134400m + 879000m

1000= 1030200m

m = 1000/1013400

m= 1013.4 grams

the final answer is 0.9706 grams