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3 votes
3 votes
5|4w-1|=5w+40


Solve for x

User Karthik Karuppannan
by
2.8k points

1 Answer

11 votes
11 votes

Answer:

w1= -1.4, w2= 3

Explanation:

I will assume that "x" is a w since there is no x within the question

Solution

w

1

=−

5

7

,w

2

=3

Alternative Form

w

1

=−1.4,w

2

=3

Evaluate

5×∣4w−1∣=5w+40

Simplify

5∣4w−1∣=5w+40

Rewrite the expression

5∣4w−1∣−5w−40=0

Separate the equation into 2 possible cases

5(4w−1)−5w−40=0,4w−1≥0

5(−(4w−1))−5w−40=0,4w−1<0

Evaluate

w=3,4w−1≥0

5(−(4w−1))−5w−40=0,4w−1<0

Evaluate

w=3,w≥

4

1

5(−(4w−1))−5w−40=0,4w−1<0

Evaluate

w=3,w≥

4

1

w=−

5

7

,4w−1<0

Evaluate

w=3,w≥

4

1

w=−

5

7

,w<

4

1

Find the intersection

w=3

w=−

5

7

,w<

4

1

Find the intersection

w=3 w=− 57

Solution

w

1

=−

5

7

,w

2

=3

Alternative Form

w 1=−1.4,w 2

=3

User Murali Murugesan
by
2.9k points