Question

A rocket traveling at 80 m/s is accelerated uniformly to 152 m/s over a 18 s interval. What is its displacement during this time?

Answer 1

Recall that with constant acceleration,

`x_f-x_i=\frac{v_i+v_f}2t`

where
`x_f-x_i` is the rocket's displacment,
`v_i` is its initial velocity,
`v_f` its final velocity, and
`t` is time. So

`x_f-x_i=\frac{80(\mathrm m)/(\mathrm s)+152\,(\mathrm m)/(\mathrm s)}2(18\,\mathrm s)=2088\,\mathrm m`

or just 2100 m if taking significant digits into account.