Question

Which two values of X are roots of the polynomial below 4x^2-6x+1

Answer 1

`4x^2-6x+1=0\\\\a=4,\ b=-6,\ c=1\\\\\Delta=b^2-4ac\\\\\Delta=(-6)^2-4(4)(1)=36-16=20\\\\\sqrt\Delta=√(20)=√(4\cdot5)=\sqrt4\cdot\sqrt5=2\sqrt5\\\\x_1=(-b-\sqrt\Delta)/(2a),\ x_2=(-b+\sqrt\Delta)/(2a)\\\\x_1=(-(-6)-2\sqrt5)/(2\cdot4)=(3-\sqrt5)/(4)\\\\x_2=(-(-6)+2\sqrt5)/(2\cdot4)=(3+\sqrt5)/(4)`