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Help with just one Geometry question.

Help with just one Geometry question.-example-1

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In the given problem we are given a pentagon.

A pentagon has 5 sides and 5 internal angles.

In order to find the required angle, we need to find the total sum of all angles of a a pentagon.

We know formula for the total sum of all angles of a a polygon is given by,

Angle sum = (n-2) *180, where n is the number of sides of the given polygon.

As we know, the given ploygon (pentagon) has 5 side, so the value of n=5.

Plugging n=5 in above formula.

(n-2)*180 = (5-2)*180.

Subtracting 5-2 first, we get 3.

Now, multiplying 3 * 180, we get 540.

So, the total sum of all angles of a Pentagon = 540°.

Given angles 131°, 108°, 107°, 110° and x.

Sum of all angles = 540

Adding angles,

131° + 108° + 107° + 110° + x = 540

456° + x = 540.

Subtractcing 456 from both sides,

456° + x - 456 = 540 - 456.

x=84°.

Therefore, required angle x=84°.

User Shabarinath Pabba
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