70.2k views
0 votes
What are the zeros of f(x)=x^2-12x+36

User Onera
by
7.2k points

2 Answers

4 votes

Answer:

x=6 only

Explanation:

User Sebastian Nemeth
by
6.6k points
6 votes

Answer:


x=6

Explanation:

We have been given a function
f(x)=x^2-12x+36. We are asked to find the zeros of our given function.

We can recognize from our given function formula that it is a perfect square as:


f(x)=x^2-12x+36=x^2-(2*6*x)+6^2=(x-6)^2

Using zero product property we will get:


(x-6)^2=0

Upon taking square root of both sides, we will get:


x-6=0

Upon adding 6 on both sides, we will get:


x-6+6=0+6


x=6

Therefore,
x=6 is a zero for our given function.

User Swagata Prateek
by
6.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.