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Find the cross product a ×
b. A = i + 3j − 2k, b = −i + 5k

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we are given


a=i+3j-2k


b=-i+5k

we can find cross product


aXb=\begin{pmatrix}1&3&-2\end{pmatrix}* \begin{pmatrix}-1&0&5\end{pmatrix}


\mathrm{Computing\:cross\:product\:of\:two\:vectors}:\quad \left(u_1,\:u_2,\:u_3\right)* \left(v_1,\:v_2,\:v_3\right)=\left(u_2v_3-u_3v_2,\:u_3v_1-u_1v_3,\:u_1v_2-u_2v_1\right)


=\begin{pmatrix}3* \:5-\left(-2* \:0\right)&-2\left(-1\right)-1* \:5&1* \:0-3\left(-1\right)\end{pmatrix}


aXb=15i-3j+3k


User Shishir Arora
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