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#17 if anyone can help. Much appreciated.

#17 if anyone can help. Much appreciated.-example-1
User Abelisto
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1 Answer

7 votes

We set up a system of equations to solve.

Let x = number books priced at $6.99 and y = number books priced $9.99.

There are 32 books bought so we have the equation:-

x + y = 32.................(1)

Now we get an equation from the costs of the books

6.99x + 9.99y = 256.68...................(2)

Solving this system of 2 equations:-

From equation (1):- y = 32 - x

Now substitute this into equation (2):-

6.99x + 9.99(32 - x) = 256.68

6.99x + 319.68 - 9.99x = 256.68

-3x = - 63

x = 21

From equation (1) y = 32 - 21 = 11

So Amber bought 21 books at 6.99 and 11 books at 9.99 dollars Answer


User Aakash Gupta
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