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Samuel tosses a football from the top of a hill. The football's height h, in feet, after t seconds is modeled by the equation h = −16t2 + 16t + 12. After how many seconds will the football reach the ground?

User Hugh Nolan
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1 Answer

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In this question it is given that Samuel tosses a football from the top of a hill. The football's height h, in feet, after t seconds is modeled by the equation


h = -16t^2 +16t+12

When football reach the ground, then value of h is 0 .

So we have to put 0 for h and solve for t. That is


-16t^2 +16t+12=0


16t^2 -16t-12=0


4(4t^2 -4t-3)=0

Dividing both sides by 4 to get rid of 4


4t^2 -4t-3=0


(2t-3)(2t+1)=0


2t-3=0 , 2t+1=0


t=3/2 , t=-1/2

And time cant be negative. SO the time by which football reach the ground is 3/2 or 1.5 seconds .

User Jagadeesh K
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