Question

An automobile uses gasoline at a rate of 35 mi/gal, which is the same as ________ km/l (1 km = 0.6214 mi, 1 gal = 3.78 l)

Answer 1

R = Rate of gasoline by automobile = 35 mi/gal

it is given that , 1 kilometer = 0.6214 miles

and 1 gallon = 3.78 liter

so

R = 35 (miles/gallon) (1 kilometer/0.6214 miles) (1 gallon/3.78 liter)

R = (35) (1/0.6214) (1/3.78) (miles x 1 kilometer/1 miles) (1 gallon/(1 gallon x 1 liter))

R = 14.9 kilometer/liter

Answer 2

Answer:
`14.9\text{km/l}`

Explanation:

Given: An automobile uses gasoline at a rate of 35 mi/gal.

`1\text{ kilometer}=0.6214 \text{ mi}\\\\\Rightarrow1\text{ mi}=(1)/(0.6214)\text{ km}\\\\\text{ gal}=3.78\text{ l}`

Now, to convert the rate from mi/ gal to km/ l , we need to multiply it by the reciprocal of 0.6214 and divide 3.78 , we get

`35 \text{mi/gal}=35*(1)/(0.6214)*(1)/(3.78)=14.9006425157\approx14.9\text{km/l}`

An automobile uses gasoline at a rate of 35 mi/gal, which is the same as
`14.9\text{km/l}`.