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Select all the points that are on the graph of the equation x+3y=12

User MattoTodd
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1 Answer

23 votes
23 votes

Answer:

(1,3), (2,2), (3,1), (4,0), (-1,5), (-2,6), (-3,7), (-4,8), (-5,9), & (-6,10)

Explanation:

First, solve to alter the equation into a slope form instead of in standard form.

x+3y=12

Because x represents the slope, we need to transfer it to the other side of the equation. By subtracting it, it'll allow the equation to only have 3y on the left side of the equation and x will become negative x which will be added on to the 12 on the right side.

x+3y=12

-x -x

+3y=-x+12

3y=-x+12

Next, you would divide the 3 underneath the y and the number 12 to allow the 3y to become y because y needs to be isolated in order for the slope intercept formula to work.

3y divided by 3 equals 3 and 12 divided by 3 is 4.

3y/3=-x+12/3

The final equation would look as follows:

y=-x+4

Hence, the y-intercept is 4 and the slope is -1.

You would then plot the origin coordinate of (0,4) and either go down one and right one or up one and left one; either way, you'll receive a negative slope looking like this: \

Some points on the graph would be: (1,3), (2,2), (3,1), (4,0), (-1,5), (-2,6), (-3,7)

Hope this helps.

User Eyespyus
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2.4k points