Question

Im almost done with it

Answer 1

Area of rectangle =
`\mathbf{x^2-4x}`

Perimeter of rectangle =
`\mathbf{4x-8}`

Explanation:

We are given:

Length of rectangle = x

Width of rectangle = x-4

We are not given if we want to find area of rectangle or perimeter of rectangle.

So, I will be finding both

Area of rectangle

The formula used is:
`Area\: of\: rectangle=Length * Width`

Putting values and finding area

`Area\: of\: rectangle=Length * Width\\Area\: of\: rectangle=x * (x-4)\\Area\: of\: rectangle=x^2-4x`

So, we get area of rectangle =
`\mathbf{x^2-4x}`

Perimeter of rectangle

The formula used is:
`Perimeter \: of\: rectangle=2(Length+ Width)`

Putting values and finding perimeter

`Perimeter \: of\: rectangle=2(Length+ Width)\\Perimeter \: of\: rectangle=2(x+ x-4)\\Perimeter \: of\: rectangle=2(2x-4)\\Perimeter \: of\: rectangle=4x-8`

So, we get perimeter of rectangle =
`\mathbf{4x-8}`

I hope, it can help in solving the question.