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Shelley's basketball team won 3/4 of their games last season. In 1/6 of the games they won, they outscored their opponents by more than 10 points. What fraction of their games did Shelley’s team win by more than 10 points?

2 Answers

5 votes

Answer:


(1)/(8)

Explanation:

This problem can be resolved with a simple multiplication, but the important thing is to analyse and know why.

First of all, this problem can be seen as a probability problem with two events: Games won (Event A) and Games won with more than 10 points (Event B).

Each event have already its probability. For Event A we have
(3)/(4). For Event B we have
(1)/(6).

So, the fact that it's being asked for the expression when they won and with more than 10 points, means an interception, a mixture of both events. In order to that ''mixture'', mathematically we multiply, because we need to calculate games won and with more than 10 points.


(3)/(4) . (1)/(6) = (3)/(24)  = (1)/(8)

User Anil Prz
by
7.6k points
3 votes

Let the total number of games be x.

Number of games Shelley's team won =
(3)/(4) x

Number of games they outscored

their opponents by more than 10 points =
(1)/(6) ×
(3)/(4) x

=
(1)/(8) x

Hence, 1/8 of the total games, Shelley's team won by 10 points.

User Amarillion
by
7.9k points
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