Given: BO : OY = 5:8. Coordinate B is located at (4,2,) ; O is located at (57/8,-3) and Y is located at (x,y).
We have to determine the coordinate Y.
We will use cross section formula which states:
The coordinates
are divided in the ratio
by the Coordinate A. So, the coordinates of A are given by the formula:
![((m_1x_2+m_2x_1)/(m_1+m_2) , (m_1y_2+m_2y_1)/(m_1+m_2))](https://img.qammunity.org/2019/formulas/mathematics/high-school/yq4y40l4ieonaf24qh3hipncs603ar1lcy.png)
Here,
![(57)/(8) = (5x+(8 * 4))/(5+8)](https://img.qammunity.org/2019/formulas/mathematics/high-school/rrr1fl8udmv25uqf8sk3m5486gqlqgd3kf.png)
![(13 * 57)/(8) = 5x+32](https://img.qammunity.org/2019/formulas/mathematics/high-school/qxireg090wsuj4vrbmvb2aijodilinpjoc.png)
![(741)/(8) = 5x+32](https://img.qammunity.org/2019/formulas/mathematics/high-school/gzxqmf6kywpptnu4vva6xq2uw3wzyilu7b.png)
![5x= 60.625](https://img.qammunity.org/2019/formulas/mathematics/high-school/s7wl4fbuhxfknfieqk3tmg92goroycxe9a.png)
x = 12.125
Now,
![-3=(5y+(8 * 2))/(5+8)](https://img.qammunity.org/2019/formulas/mathematics/high-school/jenndquzljqwy6gaqy8hqvp249rzbkpl42.png)
![-39 = 5y+16](https://img.qammunity.org/2019/formulas/mathematics/high-school/c3gogkuii3o1p6qpize2yqgbe60rsp7ymd.png)
![-55 = 5y](https://img.qammunity.org/2019/formulas/mathematics/high-school/t1qz09vpjh1w140q4762zwpjzkd5i5wzg7.png)
y = -11
So, the coordinate is Y(12.125, -11).