Answer:
Adult tickets sold = 225
Student Tickets sold = 375
Explanation:
Let:
Adult tickets sold = x
Student Tickets sold = y
Total tickets sold = 600
So, we can write: x+y = 600
Total money collected = 3037.50
Cost of 1 Adult ticket = $6.00
Cost of one Student ticket = $4.50
So, we can write: 6x+4.5y=3037.50
Now, we get a system of equations, that if solved we can find values of x and y
Let:
![x+y = 600--eq(1)\\6x+4.5y=3037.50--eq(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/sw5vyo665x20rpqquhxa9dhqy4tgwqyruq.png)
We can solve using substitution method.
Finding value of x from eq(1) and putting it in eq(2)
![We\:have\\x+y=600\\x=600-y](https://img.qammunity.org/2022/formulas/mathematics/high-school/3zallgrgsxl3586adt8z8cuuv32kdyze4k.png)
Put in eq(2)
![6x+4.5y=3037.50\\6(600-y)+4.5y=3037.50\\3600-6y+4.5y=3037.50\\-1.5y=3037.50-3600\\-1.5y=-562.5\\y=(-562.5)/(-1.5)\\y=375](https://img.qammunity.org/2022/formulas/mathematics/high-school/m3eaxlgc5fpkopucy6dlgg1wj4enub61kd.png)
So, we get value of y = 375
Now put value of y in eq(1) to find value of x
![x+y=600\\Put\:y=375\\x+375=600\\x=600-375\\x=225](https://img.qammunity.org/2022/formulas/mathematics/high-school/20sjts5awail8qwgsl90nivufhg7j0uu3g.png)
So, we get value of x = 225
The Tickets sold will be:
Adult tickets sold = x = 225
Student Tickets sold = y = 375