Question

An object (moving man) starts from rest and accelerates at a rate of 4.3m/s2 for 2.05 seconds. What is his displacement from the start position

Answer 1

We use the kinematic equation of motion,

`s= ut + (1)/(2) a t^2`

Here, s is displacement, u is initial velocity, a is acceleration and t is time.

Given
`a = 4.3 \ m/s^2` ,
`t =2.05 s` .

We take,
`u = 0` because object starts from rest.

Substituting these values in above equation, we get

`s = 0 * 2.05 \ s + (1)/(2) (4.3 \ m/s^2)(2.05 \ s)^2 \\\\ s = 9.0 \ m.`

Therefore, displacement of object from starting position is 9 m.