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Solve the problem given below

Solve the problem given below-example-1

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3 votes
x=12, the box when assembled is 2 inches tall and 8 inches long
User Jaymee
by
8.5k points
4 votes

Answer

12 in by 12 in

Step-by-step explanation

The original length = x

This makes the length of the cube made to be = x - (2×2)

= (x - 4) in

height of the cube = 2 in

Volume of the cube = (x - 4) × (x - 4) × 2 = 128

= (x² - 8x + 16) × 2 = 128

= 2x² - 16x + 32 = 128

= 2x² - 16x + 32- 128=0

= 2x² - 16x - 96 = 0

= x² - 8x - 48 = 0

lets use the factor method to solve the quadrilatic equation above,

x² - 8x - 48 = 0

proctuct = -48

sum = -8

The two factors are; -12 and 8.

(x + 8)(x - 12) = 0

So the value of x are 12 and -8. Since x is a length, it can not be negative.

∴ x = 12 in.

The original dimensions of the sheet are 12 in by 12 in.

User DobromirM
by
7.8k points

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