Question

An object initially moving 10 m/s accelerates for 6 seconds. If it moves 134 m, find the acceleration.

A. 49.3 m/s^2 B.1.02 m/s^2 C.4.11 m/s^2 D.6.17 m/s^2

Answer 1

Acceleration of the object is 4.11
`(m)/(s^(2) )`.

Given:

Initial velocity = 10
`(m)/(s)`

Time = 6 second

Distance = 134 meter

To find:

Acceleration of the object = ?

Formula used:

s = u t +
`(1)/(2) a t^(2)`

Where s = distance covered by object

u = initial velocity of the object

t = time taken by object

a = acceleration of the object

Solution:

According to second equation of motion the distance of the object is given by,

s = u t +
`(1)/(2) a t^(2)`

Where s = distance covered by object

u = initial velocity of the object

t = time taken by object

a = acceleration of the object

134 = 10 (6) +
`(1)/(2) a (6)^(2)`

134 - 60 = 18 a

74 = 18 a

a =
`(74)/(18)`

a = 4.11
`(m)/(s^(2) )`

Hence, acceleration of the object is 4.11
`(m)/(s^(2) )`.